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Proof of a(notp1,a(isp1,x)) = a(notp1,x).

----> UNIT CONFLICT at   1.93 sec ----> 820 [binary,818.1,806.1] $F.

Length of proof is 6.  Level of proof is 5.

Proof



14 [reference] x=y|x noteq(x,y) !=y noteq(x,y).
16 [reference] x y!=p1|isp1 x y =p1.
17 [reference] x y=p1|isp1 x y =p2.
23 [reference] notp1 x y=p1|notp1 x y =p2.
24 [reference] notp1 (notp1 x)=isp1 x.
25 [assumption to refute] notp1 (isp1 bad)!=notp1 bad.
26 [ur,25,14] notp1 (isp1 bad) noteq(notp1 (isp1 bad),notp1 bad)!=notp1 bad noteq(notp1 (isp1 bad),notp1 bad).
36 [para_into,26.1.1.1.2,24.1.2] notp1 (notp1 (notp1 bad)) noteq(notp1 (isp1 bad),notp1 bad)!=notp1 bad noteq(notp1 (isp1 bad),n
otp1 bad).
746 [para_into,36.1.1.1,24.1.1] isp1 (notp1 bad) noteq(notp1 (isp1 bad),notp1 bad)!=notp1 bad noteq(notp1 (isp1 bad),notp1 bad).
794 [para_into,746.1.1,16.2.1,flip.1] notp1 bad noteq(notp1 (isp1 bad),notp1 bad)!=p1.
806 [para_into,746.1.2,23.2.1,unit_del,794] isp1 (notp1 bad) noteq(notp1 (isp1 bad),notp1 bad)!=p2.
818 [ur,794,17] isp1 (notp1 bad) noteq(notp1 (isp1 bad),notp1 bad)=p2.
820 [binary,818.1,806.1] $F.



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